Can you give C program that will accept strings as input and display the total number of vowels and consonants

Can you give C program that used string and array function that will accept strings as input and display the total number of vowels and consonants.





Sample Output:





Enter a string: Venus


No. of vowels: 2


No. of Consonants: 3

Can you give C program that will accept strings as input and display the total number of vowels and consonants
You'd need something along the lines of this:





char string[256];


int vowels=0, consonants=0;





cout %26lt;%26lt; "Input string: ";


cin.getline( string, 256, '\n');





cout %26lt;%26lt; "You typed: " %26lt;%26lt; string %26lt;%26lt; endl;





int i=0;





while (string[i] != '\0') {


  if (string[i] == 'a' ||


    string[i] == 'e' ||


    string[i] == 'i' ||


    string[i] == 'o' ||


    string[i] == 'u' )


    vowels++;


else


  consonants++;





  i++;





}//end of analyzing loop





cout %26lt;%26lt; "Number of vowels in your string: " %26lt;%26lt; vowels %26lt;%26lt; endl;


cout %26lt;%26lt; "Number of non-vowels in your string:" %26lt;%26lt; consonants %26lt;%26lt; endl;